Find three consecutive integers such that the sum of the largest and 5 times the smallest is - 244

n, n + 1, n + 2 - three consecutive integers

(n + 2) + 5n = - 244

n + 2 + 5n = - 244

6n + 2 = - 244 |subtract 2 from both sides

6n = - 246 |divide both sides by 6

n = - 41

n + 1 = - 41 + 1 = - 40

n + 2 = - 41 + 2 = - 39

Answer: - 41, - 40, - 39.