Which of the following values for x and y make the equation 4x + 2y + 3 = 19 true?

x = 5, y = 3

x = 4, y = 5

x = 3, y = 2

x = 2, y = 5

To answer the question above, substitute the values of x from each choice then solve for y. This is shown below.

A. x = 5, 4 (5) + 2y + 3 = 19, y = - 7

B. x = 4, 4 (4) + 2y + 3 = 19, y = 0

C. x = 3, 4 (3) + 2y + 3 = 19, y = 2

D. x = 2, 4 (2) + 2y + 3 = 19, y = 4

From the calculations above, only the third choice has a similar value of y to the value in calculations.

Thus, the answer is letter C.