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26 December, 03:05

Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the botta

of the cone. The radius of the snow cone is 2 inches, and the height of the cone is 3 inches. If the diameter of the bubble gum is 0.5 inches, which of the following

can be used to calculate the volume of the cone that can be filled with flavored ice?

03 (3.14) (23) (3) - (3.14 (0.253)

03 (3.14) (33 (2) - (3.140.253

0313.141 (23) (3) - (3.1410:53

03 (3.1416331 (2) - (3.14) (0.5%)

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Answers (1)
  1. 26 December, 04:19
    0
    Let us first note down all the information's that are given in the question.

    Radius of the snow cone = 4 inches

    Height of the snow cone = 6 inches

    Diameter of the bubble gum = 0.8 inches

    Then

    Radius of the bubble gum = 0.4 inches

    Now

    Volume of the come = 1/3 * pi * (radius) 2 * height

    = 1/3 * 3.14 * (4) ^2 * 6

    = 3.14 * 16 * 2

    = 100.48 cubic inches

    Again

    Volume of the sphere = (4/3) * pi * (radius) ^3

    = (4/3) * 3.14 * (0.4) ^3

    = (4/3) * 3.14 * 0.064

    = 0.2679 cubic inches

    Volume of the cone

    that can be filled with flavored ice = 100.48 - 0.27

    = 100.21 cubic inches

    The correct option among all the options that are given in the question is option "d".
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