Use the unit circle to find the value of cot (-270°). Question 3 options: cot (-270°) = 1 cot (-270°) = - 1 cot (-270°) = 0 undefined

Question 3 options:

cot (-270°) = 1

cot (-270°) = - 1

cot (-270°) = 0

undefined

cot (-270) = 0

Step-by-step explanation:

given cot (-270)

In trigonometry function we will use cot (-x) = - cotx

so cot (-270) = - cot270

trigonometry table

II quadrant I quadrant (All positive)

sin θ 90+θ 90 - θ

cosec θ 180-θ 360+θ

third quadrant fourth quadrant

tan θ 180+θ cos θ 270+θ

cot θ 270 - θ sec θ 360-θ

Given

cot (-270) = - cot (270)

= - cot (180 + 90) (third quadrant above table)

= - cot 90 = 0 (cot θ positive in third quadrant

Final answer:-

cot (-270) = 0