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31 January, 19:33

In a tornado the wind velocity in meters per second can be described by the function v (p) = 12.3 sqrt 1134-3p where 'p' is th air pressure in millibars. What is the air pressure of a tornado in which the wind velocity is 49.3 meters per second?

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  1. 31 January, 23:16
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    We are given with the function

    v (p) = 12.3 √ (1134 - 3p)

    We are asked to find the air pressure when the velocity is 49.3 m/s

    Substituting this to v (p)

    49.3 = 12.3 √ (1134 - 3p)

    49.3/12.3 = √ (1134 - 3p)

    4.01 = √ (1134 - 3p)

    4.01² = √ (1134 - 3p) ²

    16.07 = 1134 - 3p

    3p = 1134 - 16.07

    3p = 1117.92

    p = 1117.92/3

    p = 372.64 millibars
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