Identify the vertex for the graph of y=3x^2+12+5.

(2,41)

(2,35)

(-2,-31)

(-2,-7)

The vertex would be D) (-2, - 7)

Step-by-step explanation:

To find the vertex, start by find the x-value. For this we can use the equation below.

x = - b/2a

In which a is the coefficient of x^2 and b is the coefficient of x.

x = - b/2a

x = - (12) / 2 (3)

x = - 12/6

x = - 2

Now that we have x, we find y by plugging - 2 in for each x.

y = 3x^2 + 12x + 5

y = 3 (-2) ^2 + 12 (-2) + 5

y = 3 (4) - 24 + 5

y = 12 - 24 + 5

y = - 7