Find two consecutive even integers such that 3 times the smaller integer is 16 more than twice the larger

n, n + 2 - two consecutive even integers

3n = 2 (n + 2) + 16 |use distributive property

3n = (2) (n) + (2) (2) + 16

3n = 2n + 4 + 16

3n = 2n + 20 |subtract 2n from both sides

n = 20

n + 2 = 20 + 2 = 22

Answer: 20, 22.