Sihui and Mark have $16 altogether. If Sihui has $2 more, she will have half as much as Mark. How much money does each of them have? (Use the elimination method to show the solution set)

Question

Mathematics

Sage Duke

14 March, 11:49

Sihui and Mark have $16 altogether. If Sihui has $2 more, she will have half as much as Mark. How much money does each of them have? (Use the elimination method to show the solution set)

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Answers (1)

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Alexzander Key · Answer 1

Sihui has $4 and Mark has $12.

Step-by-step explanation:

Let the amount that Sihui has be s.

Let the amount that Mark has be m.

Sihui and Mark have $16 altogether. This means that:

s + m = 16

If Sihui has $2 more, she will have half as much as Mark. This means that:

s + 2 = m/2

=> s = m/2 - 2

By process of elimination, put this value of s in the first equation:

m/2 - 2 + m = 16

=> 3m/2 = 16 + 2 = 18

m = (18 * 2) / 3

m = 36 / 3 = $12

=> s = 12/2 - 2

s = 6 - 2 = $4

Sihui has $4 and Mark has $12.