Suppose the depth of a lake can be described by the function y = 321 (0.976) x, where x represents the number of weeks from today. Today, the depth of the lake is 321 ft. What will the depth be in 6 weeks? Round your answer to the nearest whole number. The depth of the lake will be ft. In 6 weeks.

Question

Mathematics

Jalen Grant

17 April, 10:25

Suppose the depth of a lake can be described by the function y = 321 (0.976) x, where x represents the number of weeks from today. Today, the depth of the lake is 321 ft. What will the depth be in 6 weeks? Round your answer to the nearest whole number. The depth of the lake will be ft. In 6 weeks.

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Answers (1)

Know the Answer?

Anahi Hancock · Answer 1

The lake will be 1879.776 fts deep in six weeks.

Step-by-step explanation:

The depth of the lake as the weeks passes is given by the equation y = 321 * (0.976) * x. So if we need to find the depth of the lake in six weeks, we have to attribute that value to x and solve the equation, as seen bellow:

y = 321 * (0.976) * x = 321 * (0.976) * 6 = 1879.776 fts

The lake will be 1879.776 fts deep in six weeks.