Factor trinomials; 2v^2 + 11v + 5

(V+5) (2v+1) is the answer

(v + 5) (2v + 1)

Step-by-step explanation:

Given

2v² + 11v + 5

Consider the factors of the product of the coefficient of the v² term and the constant term which sum to give the coefficient of the v - term.

product = 2 * 5 = 10 and sum = + 11

The factors are + 10 and + 1

Use these factors to split the v - term

2v² + 10v + v + 5 (factor the first/second and third/fourth terms)

= 2v (v + 5) + 1 (v + 5) ← factor out (v + 5) from each term

= (v + 5) (2v + 1) ← in factored form