Solve this equation. (x+3) / 2 - (11-x) / 5 = 1 + (3x-1) / 20

you put x+3 over 2 and 11-x over 5 and 3x-1 over 20 as a fraction. then you have to make the denominators the same for. the common denominator will be 20 since its the highest and all the other denominators can multiply to get there. then you multiply each fraction by the top and the bottom for the first fraction of (x+3) / 2 youmultiply top and bottom by 10 then the next fraction you multiply top and bottom by 4 and for the number 1 in the equation just multiply by 20 then all the denominators cancel out and then on the top you will get10x+30-44-4x=20+3-1 then you put them all together to get 6x-14=19+3x and when you put the x's on one side and the regular number on the other side you will get 3x=33 and divide the 33 by 3 so you will get x=11 which is the answer.

X = - 19/4. x+3/2-11-x/5 - (1+3*x-1/20) = 0