How do u find the axis of symmetry for f (x) = 3 (x+4) ^2 + 1

x = - 4 is the axis of symmetry

Step-by-step explanation:

The parabola is written in the form y = a (x-h) ^2 + k

The vertex is (h, k) and the axis of symmetry is at x=h.

Given f (x) = 3 (x - - 4) ^2 + 1, the vertex is (-4,1) so the axis of symmetry is x = - 4