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25 September, 23:59

What is the radius r of the turn if θ = 20.0 ∘ (assuming the car continues in uniform circular motion around the turn) ? express your answer in meters?

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  1. 26 September, 02:51
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    The answer is 54.18 meters.

    Explanation:

    Fk = - mg + N cos (20) = 0

    Fr = N sin (20) (frictional force)

    Fr = m (a) where as a = v²:r

    By putting in the values ...

    N = mg: cos (20)

    r = v²: g tan (20) (radius equation)

    = 13.89²: 9.81 (tan 20) (gravitational force = 9.81 m/s²)

    r = 54.18 meters.
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