The length of a rectangle is 2 inches more than twice it's width. If the perimeter of the rectangle is 70 inches, find it's length and width

Let's assume width of a rectangle = a inches

than length of the rectangle = 2*a + 2

= 2a + 2 inches

perimeter of the rectangle. = 70 inches

perimeter (P) = 2 (length + width)

after substituting value of l and w we have

p = 2 (l+w)

70 = 2 (2a+2 + a)

70 = 2 (3a+2)

70 = 6a+4

70 - 4 = 6a

66 = 6a, a = 66/6 = 11

so a=11 inches, a = width

therefore width is = 11 inches

length is = 11*2+2 = 24 inches