Ask Question
10 August, 12:41

Suppose the system of linear equations has no solution. Which is NOT a possible value of the constant for the second equation?

6x + 9y = 15

2x + 3y = __

A) 5

B) 10

C) 15

D) 20

+3
Answers (1)
  1. 10 August, 13:03
    0
    A) 5

    Step-by-step explanation:

    The coefficients of the second equation are 1/3 of those of the first equation. If the constant of the second equation is also 1/3 of the constant of the first equation, then the equations are dependent, and will have an infinite number of solutions.

    The constant must be something other than 1/3·15 = 5 to make the equations inconsistent, having no solutions.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Suppose the system of linear equations has no solution. Which is NOT a possible value of the constant for the second equation? 6x + 9y = 15 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers