The area of a rectangle is (x^3 - 5x^2 + 3x - 15), and the width of the rectangle is (x^2 + 3). If area = length c width, what is the length of the rectangle?

Question

Mathematics

Kolten Waters

9 February, 08:14

The area of a rectangle is (x^3 - 5x^2 + 3x - 15), and the width of the rectangle is (x^2 + 3). If area = length c width, what is the length of the rectangle?

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Answers (1)

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Davis Mcintyre · Answer 1

Length = x-5

Step-by-step explanation:

Length = Area/width

Length = x³-5x²+3x-15 / x²+3

Re-arrange the numerator:

Length=x³+3x-5x²-15/x²+3

Take common from the numerator:

Length=x (x²+3) - 5 (x²+3) / x²+3

Length = (x²+3) (x-5) / x²+3

Length = x-5

Thus the answer is x-5 ...