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28 January, 07:31

A bag contains ten identical blue marbles and ten identical green marbles. In how many distinguishable ways can five of these marbles be put in a row if there are at least two blue marbles in the row and every blue marble is next to at least one other blue marble

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  1. 28 January, 09:52
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    Answer: 11 different rows.

    Step-by-step explanation:

    As the marbles are identical, we do not really care for permutations (as we can really not difference them)

    If we have 5 blue marbles, we have only one combination.

    B-B-B-B-B

    If we have 4 blue marbles, we have 3 combinations:

    B-B-B-B-G, G-B-B-B-B, B-B-G-B-B

    This is because the blue marbles need to be next to another blue one, so from here we can do the same analysis.

    If we have 3 of them, we have 3 combinations.

    B-B-B-G-G, G-B-B-B-G, G-G-B-B-B

    If we have 2 of them, we have 4 combinations

    B-B-G-G-G, G-B-B-G-G, G-G-B-B-G, G-G-G-B-B

    then we have 1 + 3 + 3 + 4 = 11 combinations
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