Which expression is equivalent to logc x^2-1/5x?

log (x²-1) - (log5+logx)

Step-by-step explanation:

For this problem we need to make use of two existing logarithmic properties. These are:

logM/N is equal to logM - logN logMN is equal to logM+logN

Following the first property, we can simplify the expression to:

log (x²-1) - log5x

Then, we will use the second property to the term 5x. The final form of the expression would then be:

log (x²-1) - (log5+logx)

Thus the answer is log (x²-1) - (log5+logx) ...