The larger of two numbers is six less than twice the smaller number. If the sum of the numbers is 42, find the numbers.

Answer: Smaller number is 16 and larger number is 26

Step-by-step explanation:

Let the smaller number be y.

The larger number is six less than twice the smaller number which is = (2*y) - 6 = 2y-6

The addition of the large and small number equals 42.

y + 2y - 6 = 42

3y - 6 = 42

3y = 42+6

3y = 48

y = 48/3

y = 16

The smaller number is 16

The bigger number will be 2y-6 = (2*16) - 6 = 32-6 = 26

26,16

Step-by-step explanation:

A is the smaller number