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Yesterday, 22:54

Solve 2^x=32 and rewrite this equation in a logarithmic form

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Answers (1)
  1. Yesterday, 23:11
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    x=5

    x = log2 (32)

    Step-by-step explanation:

    2^x=32

    Rewrite 32 as 2^5

    2^x = 2^5

    Since the bases are the same, the exponents have to be the same

    x=5

    2^x=32

    Take log base 2 on each side

    log2 (2^x) = log2 (32)

    x = log2 (32)
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