The function h=-16t^2 + 1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit the ground? Round to the nearest hundresth of a second?

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Mathematics

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12 December, 16:34

The function h=-16t^2 + 1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit the ground? Round to the nearest hundresth of a second?

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Answers (1)

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Damian Maxwell · Answer 1

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h (t) = - 16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h (t) equal to 0 and solve.

-16t² + 1700 = 0 Plug this into a calculator if you have one.

t = - 10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.