Two times the sum of three consecutive odd integers is fifteen more than three times the largest of the integers. Find the integers?

Answer: 5, 7, 9

Step-by-step explanation:

1st#: 2k+1

2nd#: 2k+3

3rd#: 2k+5

2 (2k+1 + 2k+3 + 2k+5) = 3 (2k+5) + 15

2 (6k + 9) = 6k + 15 + 15

12k + 18 = 6k + 30

6k = 12

k = 2

1st#: 2k+1 = 2 (2) + 1 = 5

2nd#: 2k+3 = 2 (2) + 3 = 7

3rd#: 2k+5 = 2 (2) + 5 = 9