Solve 3x2 + 6x = 8.

a. 1 plus or minus 2 square root 33

b. the quantity of negative 3 plus or minus I square root 15 all over 3

c. the quantity of negative 3 plus or minus square root 33 all over 3

d. 1 plus or minus 2 i square root 15

Answer: C

quantity of - 3 + / - square root 33 all over 3

The quantity of negative 1 plus or minus square root 33 all over 3

Step-by-step explanation:

3x2+6x=8

3x^2+6x-8=0

Quadratic formula

x=-b + or-√b^2-4ac/2a

a=3

b=6

c=-8

x=-b + or-√b^2-4ac/2a

=-6 + or - √ (6) ^2 - 4*3*-8/2*3

=-6 + or - √36 - (-96) / 6

=-6 + or-√36+96/132

=-6 + or - √132/6

=-6 + or - 2√33/6

=-6/6 + or - 2√33/6

= - 1 + or - √33/3

The quantity of negative 1 plus or minus square root 33 all over 3