Which of the following equations has both 2 and - 4 as solutions

A x2 + 6x + 8 = 0

B x2 - 2x - 8 = 0

C x2 + 2x - 8 = 0

D x2 - 2x + 8 = 0

Problem A; has - 2 and - 4 as solutions, so this is incorrect.

Problem B; has 4 and - 2 as solutions; so this is incorrect.

Problem D; has 1 + √7i and 1 - √7i as solutions, this is also incorrect

Which leaves us to problem C;

Problem C;

Factor x^2 + 2x - 8

(x - 2) (x + 4) = 0

Solve for x

x = 2, - 4

Your answer is C. x2 + 2x - 8 = 0