Ask Question
25 November, 04:59

Use the Newton-Raphson method to determine the solution of the simultaneous nonlinear equations: y=-x2+x+0.75 y+5xy=x2 Use the initial guesses of x = y = 1.2, and iterate until the 4th iteration. (Round the final answers to five decimal places.) The values of x and y are as follows: iterationxy01.21.21 0.0290321.39412 3 0.239294

+3
Answers (1)
  1. 25 November, 05:54
    0
    Step-by-step explanation:

    Let's solve for y.

    -x2+x+0.75y+5xy=x2

    Step 1: Add x^2 to both sides.

    -x2+5xy+x+0.75y+x2=x2+x2

    5xy+x+0.75y=2x2

    Step 2: Add - x to both sides.

    5xy+x+0.75y+-x=2x2+-x

    5xy+0.75y=2x2-x

    Step 3: Factor out variable y.

    y (5x+0.75) = 2x2-x

    Step 4: Divide both sides by 5x+0.75.

    y (5x+0.75)

    5x+0.75

    =

    2x2-x

    5x+0.75

    y=

    2x2-x

    5x+0.75

    Answer:

    y=

    2x2-x

    5x+0.75
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Use the Newton-Raphson method to determine the solution of the simultaneous nonlinear equations: y=-x2+x+0.75 y+5xy=x2 Use the initial ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers