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16 June, 00:21

Which of the following are roots of the polynomial function F (x) = x^3 - 5x^2 - 13x - 7

A. 7

B. 3 + Square root of 2

C. 1 + square root of 3

D. - 1

E. 1 - square root of 3

F. 3 - square root of 2

+3
Answers (2)
  1. 16 June, 01:27
    0
    D and A

    Step-by-step explanation:

    If you don't know how to solve a cubic algebraically (and who really does) then the best way is something like Desmos.

    I can't copy the graph from this computer, but the answer is two roots are

    x = - 1 and the other one is x = 7

    So you would write it as (x + 1) (x + 1) (x - 7) in factor form.

    Answer: D and A

    I got the graph finally. It is loaded below.
  2. 16 June, 02:17
    0
    The roots are: 1, - 7 and - 7

    Step-by-step explanation:

    When we put x = - 1 in F (x) it is equal to 0

    Thus, (x + 1) is factor of given function.

    When we divide F (x) by (x + 1) it gives the value (x² - 6x - 7)

    Now, factorizing x² - 6x - 7 by middle term splitting.

    x² - 6x - 7 = x² - 7x + x - 7

    ⇒ x (x - 7) + 1 (x - 7)

    ⇒ (x + 1) (x - 7)

    Thus, x³ - 5x² - 13x - 7 = (x + 1) (x + 1) (x - 7)

    Thus, Roots of the given polynomial function is x = - 1, - 1, 7

    Hence, option A and D are correct.
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