Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?

A) All integers where n ≥ 1

B) All integers where > 1

C) All integers where n ≥ 4

D) All real numbers

Question

Mathematics

Hodges

18 June, 04:49

Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?

A) All integers where n ≥ 1

B) All integers where > 1

C) All integers where n ≥ 4

D) All real numbers

+2

Answers (1)

Know the Answer?

Denise Wyatt · Answer 1

The correct option is A.

Step-by-step explanation:

According to statement a1 = 4 and r = 3. This shows that r is greater than 1.

If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.

If starting value is 4, if we put n=0, then we get 4, but if we put a negative value than we would get a number which is not a part of our sequence. Thus the correct option is All integers where n ≥ 1 ...

Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?A) All integers where n ≥ 1B) All integers where > 1C) All integers where n ≥ 4D) All real numbers

Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?

A) All integers where n ≥ 1

B) All integers where > 1

C) All integers where n ≥ 4

D) All real numbers