Ask Question
12 May, 23:22

When the positive integer "n" is divided by 3, the remainder is 2 and when "n" is divided by 5, the remainder is 1. What is the least possible value of "n" I really need this done out step by step and explained in detail. im not grasping it ...

+3
Answers (1)
  1. 13 May, 01:52
    0
    The number would be 11.

    Step-by-step explanation:

    Dividend = Divisor * Quotient + Remainder

    Given,

    "n" is divided by 3, the remainder is 2,

    So, the number = 3n + 2,

    "n" is divided by 5, the remainder is 1,

    So, the number = 5n + 1

    Thus, we can write,

    3n + 2 = 5n + 1

    -2n = - 1

    n = 0.5,

    Therefore, number must be the multiple of 0.5 but is not divided by 3 or 5,

    Possible numbers = { 1, 2, 4, 7, 8, 11 ... }

    Since, 1 and 4 do not give the remainder 2 after divided by 3,

    And, 2, 7 and 8 do not give the remainder 1 after divided by 5,

    Hence, the least positive integer number that gives remainder 2 and 1 after divided by 3 and 5 respectively is 11.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “When the positive integer "n" is divided by 3, the remainder is 2 and when "n" is divided by 5, the remainder is 1. What is the least ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers