the length of a rectangular patio is 8 feet less than twice its width. the area of the patio is 280 square feet. find the dimensions of the patio.

The length of the rectangle 'l' = 20

The width of the rectangle 'w' = 14

Step-by-step explanation:

Explanation:-

Let 'x' be the width

Given data the length of a rectangular patio is 8 feet less than twice its width

2x-8 = length

The area of rectangle = length X width

Given area of rectangle = 280 square feet

x (2x-8) = 280

2 (x) (x-4) = 280

x (x-4) = 140

x^2 - 4x - 140=0

x^2-14x+10x-140=0

x (x-14) + 10 (x-14) = 0

(x+10) (x-14) = 0

x = - 10 and x = 14

we can choose only x = 14

The width of the rectangle 14

The length of the rectangle 2x-8 = 2 (14) - 8 = 28 - 8 = 20

The length of the rectangle 'l' = 20

The width of the rectangle 'w' = 14