What is the solution to y=2x^2-8x+8

Question

Mathematics

Babykins

27 July, 06:00

What is the solution to y=2x^2-8x+8

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Answers (1)

Know the Answer?

Mo · Answer 1

x = 2 and x = 2

Step-by-step explanation:

Simplify this problem by factoring out the coefficient 2:

y=2x^2-8x+8 = > 2 (x^2 - 4x + 4)

Note that x^2 - 4x + 4 is a perfect square: (x - 2) ^2.

y=2x^2-8x+8 = 2 (x - 2) ^2

Setting this last result = to 0, we get y = 2 (x - 2) ^2 = 0, which has a repeated solution: x = 2 and x = 2.