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27 July, 06:00

What is the solution to y=2x^2-8x+8

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  1. 27 July, 09:45
    0
    x = 2 and x = 2

    Step-by-step explanation:

    Simplify this problem by factoring out the coefficient 2:

    y=2x^2-8x+8 = > 2 (x^2 - 4x + 4)

    Note that x^2 - 4x + 4 is a perfect square: (x - 2) ^2.

    y=2x^2-8x+8 = 2 (x - 2) ^2

    Setting this last result = to 0, we get y = 2 (x - 2) ^2 = 0, which has a repeated solution: x = 2 and x = 2.
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