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4 February, 15:12

How do you solve this? r^2+32=12r

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Answers (1)
  1. 4 February, 17:24
    0
    r = {-8, - 4}

    Step-by-step explanation:

    Simplifying

    r2 = - 32 + - 12r

    Solving

    r2 = - 32 + - 12r

    Solving for variable 'r'.

    Reorder the terms:

    32 + 12r + r2 = - 32 + - 12r + 32 + 12r

    Reorder the terms:

    32 + 12r + r2 = - 32 + 32 + - 12r + 12r

    Combine like terms: - 32 + 32 = 0

    32 + 12r + r2 = 0 + - 12r + 12r

    32 + 12r + r2 = - 12r + 12r

    Combine like terms: - 12r + 12r = 0

    32 + 12r + r2 = 0

    Factor a trinomial.

    (8 + r) (4 + r) = 0

    Subproblem 1

    Set the factor ' (8 + r) ' equal to zero and attempt to solve:

    Simplifying

    8 + r = 0

    Solving

    8 + r = 0

    Move all terms containing r to the left, all other terms to the right.

    Add '-8' to each side of the equation.

    8 + - 8 + r = 0 + - 8

    Combine like terms: 8 + - 8 = 0

    0 + r = 0 + - 8

    r = 0 + - 8

    Combine like terms: 0 + - 8 = - 8

    r = - 8

    Simplifying

    r = - 8

    Subproblem 2

    Set the factor ' (4 + r) ' equal to zero and attempt to solve:

    Simplifying

    4 + r = 0

    Solving

    4 + r = 0

    Move all terms containing r to the left, all other terms to the right.

    Add '-4' to each side of the equation.

    4 + - 4 + r = 0 + - 4

    Combine like terms: 4 + - 4 = 0

    0 + r = 0 + - 4

    r = 0 + - 4

    Combine like terms: 0 + - 4 = - 4

    r = - 4

    Simplifying

    r = - 4

    Solution

    r = {-8, - 4}
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