Ask Question
17 November, 02:18

Five consecutive multiples of 3 yield a sum that is equal to the product of 7 and 15. What are these multiples?

+4
Answers (1)
  1. 17 November, 02:47
    0
    15, 18, 21, 24, 27

    Step-by-step explanation:

    Five multiples of 3 means we have 5 terms we are adding together to = 105.

    For the sake of having something to base each one of these terms on, let's say that the first term is 3. It's not, but 3 is a multiple of 3 and we have to start somewhere. These terms go up by the next number that is divisible by 3. After 3, the next number that is divisible by 3 is 6. The next one is 9, the next is 12, the last would be 15.

    Let's then say that 3 is the first term, and we are going to say that is x.

    To get from 3 to 6, we add 3. Therefore, the second term is x + 3.

    To get from 3 to 9, we add 6. Therefore, the third term is x + 6.

    To get from 3 to 12, we add 9. Therefore, the fourth term is x + 9.

    To get from 3 to 15, the last term, we add 12. Therefore, the last term is x + 12.

    The sum of these terms will then be set to equal 105:

    x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 105

    We don't need the parenthesis to simplify so we add like terms to get

    5x + 30 = 105. Subtract 30 from both sides to get

    5x = 75 so

    x = 15

    That means that 15 is the first multiple of 3.

    The next one is found by adding 3 to the first: so 18

    The next one is found by adding 6 to the first: so 21

    The next one is found by adding 9 to the first: so 24

    The last one is found by adding 12 to the first: so 27

    15 + 18 + 21 + 24 + 27 = 105

    Notice that all the numbers are, in fact, consecutive multiples of 3 as the instructions stated.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Five consecutive multiples of 3 yield a sum that is equal to the product of 7 and 15. What are these multiples? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers