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21 February, 17:16

Jennifer scores a 77 on her algebra 2 test. The mean on the test was 73. The standard deviation on the test was 5. What was her Z-score

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  1. 21 February, 20:34
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    0.80

    Step-by-step explanation:

    The z-score is found from the formula ...

    Z = (X - μ) / σ

    Z = (77 - 73) / 5 = 4/5 = 0.80

    Jennifer's Z-score was 0.80.
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