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21 August, 12:56

If $5,200 is invested at a rate of 8.6% compounded quarterly, how long will it take, to the nearest hundredth of a year, until the investment is worth $11,600?

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  1. 21 August, 14:27
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    t = 8.15 (to the nearest hundredth of a year

    Step-by-step explanation:

    In this question, we are asked to calculate the number of years (rounded off) it will take an investment which is compounded quarterly to worth a certain amount.

    To compute this, we have to use the formula for compound interest.

    Mathematically the said amount A is;

    A = P (1+r/n) ^nt

    Where P is the invested amount, r is the interest rate, n is the number of times investment is compounded per year and t is the number of years.

    In this, we identify the parameters as follows;

    A = $11,600, P = $5,200, n = 4 (quarterly means every 3 months), t = ?, r = 8.6%

    11,600 = 5200 (1 + 0.086/4) ^4t

    Dividing both side by 5,200;

    2 = (1+0.0215) ^4t

    2 = (1.0215) ^4t

    Taking logarithm of both sides;

    Log 2 = Log (1.0215) ^4t

    Log 2 = 4tLog 1.0215

    4t = Log 2/Log 1.0215

    4t = 32.5848

    t = 8.1462

    t = 8.15 (to the nearest hundredth of a year)
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