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Yesterday, 23:31

When p (x) = x^3+ax+b is divided by x-1 the remainder is 2. When px is divided by x-2 the remainder is 1. Find the values of a and b?

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  1. Yesterday, 23:55
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    a = - 8 and b = 9

    Using the Remainder Theorem.

    p (x) divided by (x - a) has remainder p (a)

    p (1) = 1³ + a + b = 2⇒ 1 + a + b = 2 ⇒ a + b = 1 ... (1)

    p (2) = 2³ + 2a + b = 1 ⇒ 8 + 2a + b = 1 ⇒ 2a + b = - 7 ... (2)

    (2) - (1) gives a = - 8

    substitute a = - 8 into (1) : - 8 + b = 1 ⇒ b=9
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