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28 April, 12:08

What would be the normal weight of a chair if the coefficient of friction between it and the floor is 0.38 and the force needed to push it is 88 lbs.?

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  1. 28 April, 14:41
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    Step-by-step explanation:

    μ = 0.38

    F = 88lbs

    N = ?

    The force acting on a surface F =

    F = μN

    Where F = force acting on the body

    N = Normal force

    μ = coefficient of static friction

    N = F / μ

    N = 88 / 0.38

    N = 231.578N

    N = 231.6N

    The normal force acting on the body is 231.6N
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