4x2 + 19x-5

Which two binomials are factors of the trinomial?

The factors are (4x-1) (x+5).

Step-by-step explanation:

4x^2+19x-5

Break the middle term:

First multiply the coefficient of first term by the constant.

4*5=20

Now find any two numbers whose product = 20 and whose sum is equal to the middle term.

20*1 = 20

20-1 = 19

Now break the middle term:

4x^2+20x-x-5

Now group the first two terms and last two terms:

(4x^2+20x) - (x+5)

Now take the common from each group.

4x (x+5) - 1 (x+5)

(4x-1) (x+5).

Thus the factors are (4x-1) (x+5) ...

(4x - 1) (x + 5)

Step-by-step explanation:

4x2 + 19x-5

(4x) (x)

We need to get - 5 The factors are - 1 and 5 and 1 and - 5

4*5 = 20

so the 5 will be on the outside We do this because we have + 19 on the inside

(4x - 1) (x + 5)

Lets check

FOIL

4x^2 + 20x - x - 5 = 4x^2 + 19x-5