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2 April, 15:20

How many solutions does the following equation have? 12z - 6 + 15z = 27z - 5

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  1. 2 April, 15:31
    0
    Zero because you combine 12z and 15z because they are like terms giving you 27z. The equation now looks like 27z-6=27z-5. Subtract 27z on both sides leaving you - 6=-5 which is false. So the equation has 0 solutions.
  2. 2 April, 15:37
    0
    WHO CARE Step-by-step explanation:

    i do XD
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