Justin, cam and Ben are playing a board game where exactly one player will win. Ben estimates that Justin has a 20% chance of winning each game and that cam has a 50% chance of winning each game?

Question:

Justin, Cam, and Ben are playing a board game where exactly one player will win. Ben estimates that Justin has a 20%, percent chance of winning each game and that Cam has a 50%, percent chance of winning each game. What is the probability that Ben will win the board game?

Answer: 30%

Step-by-step explanation:

Given the following:

Justin's chance of winning each game = 20%

Cam's chance of winning each game = 50%

Therefore, probability of:

Justin winning = 20/100 = 0.2

Cam winning = 50/100 = 0.5

Overall probability = 100% = 1

Therefore,

P (Justin winning) + P (Cam winning) + P (Ben winning) = 1

0.2 + 0.5 + P (Ben winning) = 1

P (Ben winning) = 1 - 0.7

P (Ben winning) = 0.3

0.3 = 30%