A group of seven adults went to the movies. The total cost of the movie tickets was $30. This doesn't seem possible, does it? After all, 30 is not evenly divisible by 7. Ah, but there's a hitch. The reason that $30 was the total cost was that some members of the group were senior citizens, so they got to see the movie at half price. How many of the group were senior citizens, and how much did the tickets cost?

Question

Mathematics

Jerome Livingston

15 August, 18:51

A group of seven adults went to the movies. The total cost of the movie tickets was $30. This doesn't seem possible, does it? After all, 30 is not evenly divisible by 7. Ah, but there's a hitch. The reason that $30 was the total cost was that some members of the group were senior citizens, so they got to see the movie at half price. How many of the group were senior citizens, and how much did the tickets cost?

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Reyna Solis · Answer 1

no. of senior citizens=x

no. of other people=7-x

cost=30=k (7-x) + (k/2) x. k is the cost of a ticket

k (7-x+x/2)

k (7-x/2) - 30=0

k=60 / (14-x)

now do trial and error substitution for (x<7) until u get a whole number for k also (k<30). if you have the skills you can suggest the number yourself

ie x = 2, k=5$