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29 April, 12:04

Simplify log (x2-y2) - log (x-y) =

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  1. 29 April, 12:34
    0
    Remember:

    log A - log B=log (A/B)

    (a ²-b²) = (a+b) (a-b).

    Therefore

    log (x²-y²) - log (x-y) = log[ (x²-y²) / (x-y) ] = log[ (x+y) (x-y) / (x-y) ]=log (x+y)

    Answer: log (x²-y²) - log (x-y) = log (x+y)
  2. 29 April, 13:56
    0
    Using the law of logarithm. LogA - LogB = Log (A/B)

    log (x²-y²) - log (x-y) = log ((x²-y²) / (x-y))

    Note by difference of two squares, (x²-y²) = (x-y) (x+y)

    Simplifying (x²-y²) / (x-y) = (x-y) (x+y) / (x-y) = (x+y)

    Therefore log (x²-y²) - log (x-y) = log ((x²-y²) / (x-y)) = log ((x-y) (x+y) / (x-y)) = log (x+y)
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