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17 April, 13:21

Perform the indicated operation.

3k+6 / (k-2) + (2-k) = answers::: 3, - 3,3k+6/k-2,3k+6/k+2

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  1. 17 April, 16:39
    0
    3 is the correct option.

    Step-by-step explanation:

    The given expression is:

    3k+6 / (k-2) + (2-k)

    Break the numerators:

    3k / (k-2) + 6 / (2-k)

    Now Re-arrange the term (2-k) in the denominator as (-k+2)

    3k / (k-2) + 6 / (-k+2)

    Now takeout - 1 as a common factor from (-k+2)

    3k / (k-2) + 6/-1 (k-2)

    Now move a negative (-1) from the denominator of 6/-1 (k-2) to the numerator

    3k / (k-2) + - 1*6 / (k-2)

    Now take the L. C. M of the denominator which is k-2 and solve the numerator

    3k - 6 / (k-2)

    Take 3 as a common factor from the numerator:

    3 (k-2) / (k-2)

    k-2 will be cancelled out by each other:

    Thus the answer will be 3.

    The correct option is 3 ...
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