5 squirrels were found to have an average weight of 8.9 ounces with a sample standard deviation is 0.9. Find the 95% confidence interval of the true mean weight.

Answer: (8.11, 9.69)

the 95% confidence interval of the true mean weight

= (8.11, 9.69)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.9

Standard deviation r = 0.9

Number of samples n = 5

Confidence interval = 95%

z (at 95% confidence) = 1.96

Substituting the values we have;

8.9+/-1.96 (0.9/√5)

8.9+/-1.96 (0.4025)

8.9+ / - 0.79

= (8.11, 9.69)

Therefore at 95% confidence interval (a, b) = (8.11, 9.69)