Find three consecutive even integers that have a sum that is zero

-2, 0, + 2

Step-by-step explanation:

Using one variable in different expression for each number, we can set up an equation equal to '0':

first integer: x

second integer: x + 2

third integer: x + 4

The sum of the integers is equal to '0':

x + x + 2 + x + 4 = 0

Combine like terms: 3x + 6 = 0

Subtract 6 from both sides: 3x + 6 - 6 = 0 - 6 or 3x = - 6

Divide by 3 on both sides: 3x/3 = - 6/3

Solve for x = - 2

second integer: x + 2 = - 2 + 2 = 0

third integer: x + 4 = - 2 + 4 = 2