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5 January, 13:17

The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 12.8° If skyscraper B is 1479 feet tall how far apart are the two

skyscrapers? Assume the bases of the two buildings are at the same elevation.

feet.

The distance from skyscraper A to skyscraper B is

(Round to two decimal places as needed.)

+5
Answers (1)
  1. 5 January, 15:29
    0
    6509.84 ft to the nearest hundredth.

    Step-by-step explanation:

    We have a right triangle in which the opposite side is 1479 ft and we need to find the adjacent side:

    Tan 12.8 = opposite / adjacent side

    tan 12.8 = 1479 / x

    x = 1479/tan 12.8

    = 6509.84 ft.
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