What is the vertex of the quadratic function below? Y=x^2-8x+1 A. (-8,129) B. (8,1) C. (4,-15) D. (-4,15)

Question

Mathematics

Moises Zamora

12 August, 04:27

What is the vertex of the quadratic function below? Y=x^2-8x+1 A. (-8,129) B. (8,1) C. (4,-15) D. (-4,15)

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Answers (1)

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Dana · Answer 1

The correct answer is C. (4, - 15)

Step-by-step explanation:

In order to find any vertex, start by finding the x value. We can do this by using - b/2a in which a is the coefficient of x^2 and b is the coefficient of x.

-b/2a

- (-8) / 2 (1)

8/2

4

Now we know the value of x is 4. This gives us the only option being C