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12 August, 20:09

If f (x) = x^2-3x+5 and g (x) = 3x. find the product of the function.

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Answers (2)
  1. 12 August, 20:21
    0
    3x³ - 9x² + 15x

    Step-by-step explanation:

    f (x) * g (x)

    = 3x (x² - 3x + 5) ← distribute parenthesis by 3x

    = 3x³ - 9x² + 15x
  2. 12 August, 21:53
    0
    The product of the function f (x) = x² - 3x + 5 and g (x) = 3x is;

    3x³ - 9x² + 15x

    Step-by-step explanation:

    The product of the function is simply f. g (x) = f (x). g (x)

    = (x²-3x+5). (3x)

    We will go ahead and open the bracket by multiplying each variable in the parenthesis by 3x

    (x²-3x+5). (3x) = 3x³ - 9x² + 15x

    (That is; 3x multiplied by (x²) will give 3x², 3x multiply by (-3x) will give 9x² and 3x multiply by (5) will give 15x)

    Then check if we can further simplify, since the variables are x³, x² and x, we can no longer simplify.

    So our final answer is 3x³ - 9x² + 15x

    f. g (x) = 3x³ - 9x² + 15x

    Therefore the product of the function f (x) = x² - 3x + 5 and g (x) = 3x is 3x³ - 9x² + 15x
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