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5 October, 01:19

What is the surface area of the cone? (radius 10in height 26in)

A) 425pi in2

B) 460pi in2

C) 360pi in2

D) 390pi in2

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Answers (1)
  1. 5 October, 04:30
    0
    C) 360pi in2

    Step-by-step explanation:

    Given:

    radius, r = 10in

    height, h=26in

    surface area of the cone, T. S. A=?

    T. S. A=πrl + πr^2

    =π (10) (26) + π (10) ^2

    =260π+100π

    =360π^2!
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