Ask Question
28 March, 13:25

There are 3 red balls, 5 green balls, and 1 yellow ball in a hat. If you draw the yellow ball, you gain $10. If you draw any of the red balls, you gain $4. If you draw a green ball, you lose $3. If you were to play this game 25 times, replacing the drawn ball each time, how much money can you expect to gain or lose?

+1
Answers (1)
  1. 28 March, 15:35
    0
    19.44

    Step-by-step explanation:

    We have the following information:

    3 red balls, 5 green balls, and 1 yellow ball

    In total there are 3 + 5 + 1 = 9 balls.

    We calculate the probability of each:

    Network: 3/9

    Green: 5/9

    Yellow: 1/9

    Each one corresponds a price in profit or losses:

    Network: 4

    Green: - 3

    Yellow: 10

    So in total it would be the sum of the multiplication of the probability and the price and then multiply everything by 25:

    (4 * 3/9 + - 3 * 5/9 + 10 * 1/9) * 25 = (0.777) * 25

    = 19.44
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “There are 3 red balls, 5 green balls, and 1 yellow ball in a hat. If you draw the yellow ball, you gain $10. If you draw any of the red ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers