Nine disks are numbered from 1 to 9 and placed in a box. One disk is

selected at random and not replaced. Another disk is randomly selected.

What is the probability of selecting two even numbers?

The probability of selecting two even numbers is 1/6.

Step-by-step explanation:

Nine disks are numbered from 1 to 9 and placed in a box.

The total number of disks = 9

The question is asked to find the probability of selecting two even numbers.

We know that, the disks in the box are {1,2,3,4,5,6,7,8,9}. The even number disks are {2,4,6,8}.

The number of even number disks = 4 disks.

To find the probability of selecting two even numbers without replacement:

P (first even disk) = No. of even disks / Total disks

⇒ 4 / 9

P (second even disk) = No. of remaining even disks / Total disks

⇒ 3 / 8

P (two even disks without replacement) = 4/9 * 3/8

⇒ 12 / 72

⇒ 1 / 6

∴ The probability of selecting two even numbers is 1/6.